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Derivation

\begin{figure}\psfig{figure=/home/powell/teach/biomath/bucket.ps,width=3.1in}\end{figure}

The Torricelli model for the draining bucket is based on two physical concepts:

  1. The Bernoulli relationship between pressure, $P$, density, $\rho$ and speed, $u$ for fluid along a streamline:

    \begin{displaymath}
\Delta P = \frac12 \rho u^2,
\end{displaymath}

  2. The hydrostatic relationship between changes in pressure over the height of a fluid column and gravity (acceleration $g$), fluid density $\rho$ and the height $h$ of the column:

    \begin{displaymath}
\Delta P = \rho g h.
\end{displaymath}

Equating these two gives a relationship between height of the fluid above the hole and the speed at which it spews forth,

\begin{displaymath}
u = \sqrt{2 g h}.
\end{displaymath}

The because the volume lost of fluid in the bucket must equal the flux of fluid through the bucket's hole (with area $a$),

\begin{displaymath}
\frac{dV}{dt} = - u a,
\end{displaymath}

and using the fact that (for a bucket with regular sides and constant cross section in height) $V=A h + V_0$,

\begin{displaymath}
- u a = \frac{dV}{dt} = \frac{d}{dt} \left[A h + V_0 \right] =
A\frac{dh}{dt} .
\end{displaymath}

Substituting in the relationship $u=\sqrt{2gh}$ from above gives a differential equation for height of the fluid, $h$, as a function of time:

\begin{displaymath}
\frac{dh}{dt} = -\frac{a\sqrt{2 g}}{A} \sqrt{h} . \hspace{1.5in} (*)
\end{displaymath}


next up previous
Next: Solution Up: The Torricelli Model Previous: The Torricelli Model
James Powell
2000-07-30